Question

数学分式练习

Answer 1

原式

=a(a^2-1)/(a^2-1)+(a-1)/(a^2-1)-a^2(a+1)/(a^2-1)+2/(a^2-1)

=[a(a^2-1)+(a-1)-a^2(a+1)+2]/(a^2-1)

=(a^3-a+a-1-a^3-a^2+2)/(a^2-1)

=(-a^2+1)/(a^2-1)

=-1

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