(ax^2+bx+1)(2x^2-3x+1)
=2ax^4-3ax^3+ax^2+2bx^3-3bx^2+bx+2x^2-3x+1
=2ax^4-(3a-2b)x^3+(a-3b+2)x^2+(b-3)x+1
因为不含x的平方的项,也不含x的项
所以a-3b+2=0,且b-3=0
解得a=7,b=3
(ax^2+bx+1)(2x^2-3x+1)
=2ax^4-3ax^3+ax^2+2bx^3-3bx^2+bx+2x^2-3x+1
=2ax^4-(3a-2b)x^3+(a-3b+2)x^2+(b-3)x+1
因为不含x的平方的项,也不含x的项
所以a-3b+2=0,且b-3=0
解得a=7,b=3