原式=[2(x+3)(x-3)/(x-2)²]÷[-(x-3)(x+3)/(x+3)(x-2)]
=-[2(x+3)(x-3)/(x-2)²]×[(x-2)/(x-3)]
=-[2(x+3)(x-3)(x-2)/[(x-2)²(x-3)]
=-2(x+3)/(x-2)
=-2*(-1)/(-6)
=-1/3
原式=[2(x+3)(x-3)/(x-2)²]÷[-(x-3)(x+3)/(x+3)(x-2)]
=-[2(x+3)(x-3)/(x-2)²]×[(x-2)/(x-3)]
=-[2(x+3)(x-3)(x-2)/[(x-2)²(x-3)]
=-2(x+3)/(x-2)
=-2*(-1)/(-6)
=-1/3