三式相加得到：7(x+y+z) = 49,所以 x+y+z = 7,2x+2y+2z = 14 (1)
用三个式子分别减去 (1) 式即得：x = 3,y = 5,z = -1.
｛2x+3y+2z=19｛3x+2y+2z=17｛2x+2y+3z=13
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