(2)由题意知,硝酸是过量的,以铜为标准进行计算,设生成的气体的体积为xL,
n(Cu)=19.2g64g/mol=0.3mol
3Cu+8HNO3(稀)=3Cu(NO3)2+2NO↑+4H2O
3 2×22.4L
0.3mol xL
x=4.48
故答...
(2)由题意知,硝酸是过量的,以铜为标准进行计算,设生成的气体的体积为xL,
n(Cu)=19.2g64g/mol=0.3mol
3Cu+8HNO3(稀)=3Cu(NO3)2+2NO↑+4H2O
3 2×22.4L
0.3mol xL
x=4.48
故答...