计算(-2)∧0+lg0.01+(4/9)∧1/3
1个回答
(-2)∧0+lg0.01+(4/9)∧1/3
=1+(-2)+[(2/3)²]^(1/3)
=-1+(2/3)^(2/3)
=-1+³√(2/3)²
=-1+³√(4/9)
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