Question

分式的乘除法计算：：x²-4y²/x²+2xy+y²÷x+2y/x²+

Answer 1

原式=[(x+2y)(x-2y)/(x+y)²]÷[(x+2y)/x(x+y)]

=(x+2y)(x-2y)x(x+y)/[(x+y)²(x+2y)]

=(x-2y)x/(x+y)

=(x²-2xy)/(x+y)