Question

微积分的 题 最后一步|dx/(x-3)(x+2)

Answer 1

∫ dx/(x-3)(x+2)

=∫ [1/(x-3)-1/(x+2)]/5 dx

=(1/5) {∫ [1/(x-3)]dx-∫ [1/(x+2)]dx}

=(1/5)(ln|x-3|-ln|x+2|)+C

=(1/5)ln|(x-3)/(x+2)|+C

C为任意常数