简算1+3/2+5/4+7/8+9/16+...+4003/2^2001

3个回答

  • S = 1+3/2+5/4+7/8+9/16+...+4003/2^2001

    两端同时乘 1/2

    S/2 = 1/2 + 3/4 + 5/8 + 7/16 + 9/32 + …… + 4001/2^2001 + 4003/2^2002

    两式相减

    S - S/2

    = 1 + (3/2 - 1/2) + (5/4 - 3/4) + (7/8 - 5/8) + …… + (4003/2^2001 -4001/2^2001) - 4003/2^2002

    S/2 = 1 + 2*(1/2 + 1/4 + 1/8 + …… + 1/2^2001) - 4003/2^2002

    = 1 + 2 * (1/2) * [1 - (1/2)^2001]/(1 -1/2) - 4003/2^2002

    = 1 + 2 * ( 1 - 1/2^2001) - 4003/2^2002

    = 3 - 1/2^2000 - 4003/2^2002

    = 3 - 1/2^2000 * ( 1 + 4003/2^2)

    = 3 - 4007/2^2002

    S = 6 - 4007/2^2001