记总得分为ξ,ξ的可能值为-300,-100,100,300.
P(ξ=-300)=0.23=0.008,P(ξ=-100)=3×0.22×0.8=0.096,
P(ξ=100)=3×0.2×0.82=0.384,P(ξ=300)=0.83=0.512,
所以ξ的概率分布列
根据ξ的概率分布,可得ξ的期望
Eξ=(-300)×0.08+(-100)×0.096+100×0.384+300×0.512=180.
故答案为:180.
记总得分为ξ,ξ的可能值为-300,-100,100,300.
P(ξ=-300)=0.23=0.008,P(ξ=-100)=3×0.22×0.8=0.096,
P(ξ=100)=3×0.2×0.82=0.384,P(ξ=300)=0.83=0.512,
所以ξ的概率分布列
根据ξ的概率分布,可得ξ的期望
Eξ=(-300)×0.08+(-100)×0.096+100×0.384+300×0.512=180.
故答案为:180.