1.√3=1+(√3-1),则a=√3-1,b=-(-4-2√3)=4+2√3,
-a^2+b=-(√3-1)^2+(4+2√3)
=-(4-2√3)+(4+2√3)=4√3.
2.由m-2007≥0 ,得m≥2007,2007-m≤0,2006-m≤-1
√(2006-m)^2+ √(m-2007)=m,化为
m-2006+√(m-2007)=m,√(m-2007)=2006,
m-2007=2006^2,故m-2006^2=2007.
1.√3=1+(√3-1),则a=√3-1,b=-(-4-2√3)=4+2√3,
-a^2+b=-(√3-1)^2+(4+2√3)
=-(4-2√3)+(4+2√3)=4√3.
2.由m-2007≥0 ,得m≥2007,2007-m≤0,2006-m≤-1
√(2006-m)^2+ √(m-2007)=m,化为
m-2006+√(m-2007)=m,√(m-2007)=2006,
m-2007=2006^2,故m-2006^2=2007.