Question

y/3-x+1/6=3 2(x-y/2)=3(x+y/18)要过程呦!答案是x=-7,y=6

Answer 1

y/3-(x+1)/6=3 两边乘以6 得 2y-(x+1)=18

x-2y+19=0 两边乘以6

6x-12y+19*6=0(1)

2(x-y/2)=3(x+y/18) 化简得 2x-y=3x+y/6 两边乘以6 得12x-6y=18x+y

6x+7y=0 (2)

(1)-(2)

-19y+19*6=0

y=6

带回(2)

6x+7*6=0

x=-7