Question

解复合函数 ln1-3x/4x+1 答案是7/3x-1*4x+1 要求每一步都要说清楚·谢谢··

Answer 1

[ln(1-3x)/(4x+1)]'

=(4x+1)/(1-3x) [(1-3x)/(4x+1)]'

=(4x+1)/(1-3x) {[(1-3x)'(4x+1)-(1-3x)(4x+1)']/(4x+1)^2}

=(4x+1)/(1-3x) {[(-3)(4x+1)-4(1-3x)]/(4x+1)^2}

=(4x+1)/(1-3x) [(-7)/(4x+1)^2]

=(-7)/[(1-3x)(4x+1)]

=7/[(3x-1)(4x+1)]