Question

如图,角1=角2,角3=角4,角A=110°求x的值

Answer 1

在△ABC中,

∠ABC+∠ACB+∠A=180°

∵∠A=110°

∴∠ABC+∠ACB=180°-∠A=180º-110°=70°

∵∠1=∠2,∠3=∠4

∴（∠1﹢∠2﹢∠3﹢∠4）=70°

即2﹙∠2﹢∠4﹚=70°

∠2﹢∠4=35°

∴x=180°-﹙∠2﹢∠4﹚=180°-35°=145°