函数y=cos(π/6)cos(2x)+sin(π/6)sin(2x)的单调递减区间是?
2个回答
y=cos(π/6)cos(2x)+sin(π/6)sin(2x)
=cos(2x-π/6)
2x-π/6在[2kπ,2kπ+π]单调递减
x在[kπ+π/12,kπ+7π/12]单调递减
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