Question

Matlab解题：设函数f(x)=x+sin2x,x0=π/2,要求(1)在x0≤x≤x0+π/2的区间内画出y=f(x

Answer 1

x0=2*pi;

x=x0:0.001:x0+pi/2;

y=x+sin(2*x);

plot(x,y);

grid;