Question

求函数y=x^2-(1/2)x^4的极大值和极小值,

Answer 1

y=x^2-(1/2)x^4=-1/2x^4+x^2=-1/2(x^4-2x^2)=-1/2(x^2-1)^2+1/2

所以y的最大值为当x^2=1时 取得y=1/2

没有极小值.