设所求方程是:x^2/a^2+y^2/b^2=1,(a>b>0),
根据题意:b=1,c/a=√3/2,因为b^2=a^2-c^2,所以:1=a^2-c^2,即:a^2=1+c^2,
由c/a=√3/2得:c^2=3a^2/4,所以:a^2=1+3a^2/4,解得:a^2=4,
故:所求方程是:x^2/4+y^2=1
设所求方程是:x^2/a^2+y^2/b^2=1,(a>b>0),
根据题意:b=1,c/a=√3/2,因为b^2=a^2-c^2,所以:1=a^2-c^2,即:a^2=1+c^2,
由c/a=√3/2得:c^2=3a^2/4,所以:a^2=1+3a^2/4,解得:a^2=4,
故:所求方程是:x^2/4+y^2=1