Question

若有理数A,B满足|3a+1|+（2b-1)的二平方=0,求3a²-2b三次方/ab的值?

Answer 1

因为

|3a+1|>=0,(2b-1)²>=0

|3a+1|+(2b-1)²=0,

所以：3a+1=0,2b-1=0

a=-1/3,b=1/2

(3a^2-2b^3)/ab

=7/2