已知x²+2xy-8y²=0(y≠0),求(x-y)/(x+y)的值
1个回答
x²+2xy-8y²=0(y≠0),
等价于(x+4y)(x-2y)=0
所以x=-4y或x=2y
(x-y)/(x+y)
=-5y/-3y
= 5/3
或
(x-y)/(x+y)
=y/3y
=1/3
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