Question

已知√2≈1.414,√3=≈1.732,求(√3/2)-(1/6×√24减3/2×√12)+(√3减√2)的值

Answer 1

已知√2≈1.414,√3=≈1.732,

(√3/2)-(1/6×√24-3/2×√12)+(√3-√2)

=(√3/2)-(1/6×2√6-3/2×2√3)+(√3-√2)

=(√3/2)-(1/3×√6-3×√3)+(√3-√2)

=√3/2+3√3+√3-√2-√6/3

=9/2×√3-√2-√2×√3/3

=9/2×1.732-1.414-1.732×1.414/3

=5.564