cos^4(x)-sin^4(x)
=[cos^2(x)-sin^2(x)][cos^2(x)+sin^2(x)] (其中[cos^2(x)+sin^2(x)]=1)
=[cos^2(x)-sin^2(x)] (就是cos2x的展开式 )
=cos2x
cos^4(x)-sin^4(x)
=[cos^2(x)-sin^2(x)][cos^2(x)+sin^2(x)] (其中[cos^2(x)+sin^2(x)]=1)
=[cos^2(x)-sin^2(x)] (就是cos2x的展开式 )
=cos2x