logx+1(2-x)>1解不等式

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当0＜x+1＜1即-1＜x＜0时,logx+1(2-x)>1=logx+1(x+1) 则2-x＜x+1得x>1/2,所以是空集.当x+1>1 即x>0时,logx+1(2-x)>1=logx+1(x+1),则2-x>x+1得x