Question

x+4的绝对值+（y-1)方=0,求3x方-2xy-7x方+8xy+6x方的值

Answer 1

x+4=0,y-1=0 x=-4,y=1 3x^2-2xy-7x^2+8xy+6x^2 =2x^2+6xy =2*(-4)^2+6*(-4)*1 =32-24=8