设2x+y=10为(1),x-y+z=4为(2),3x-y-z=0为(3).(2)+(3):4x-2y=4(4) 将(4)+(1)+(1)=8x=24 x=3 则y=4 ,z=5
{2x+y=10 {x-y+z=4 {3x-y-z=0
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相关问题
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{x+2y+4z=0{2x-y+3z=-10{3x+y+2z=5
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已知4x-3y-6z=0,x+2y-7z=0,求5x+2y-z/2x-3y-10z
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x+y+2z=5 2x-y-z=4 3x+y-3z=10
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3x+2y+z=4 x+y+z=10 2x+3y-z=1
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已知x+2y-4z=0,3x-y-z=0,则3x+2y+z/x+2y+z=
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已知3x+4y+5z=0,2x+3y-4z=0,求(x+y+z)/(x-y+z)
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x-5y-3z=0 y+z-3x=3 x+y+3z=14 y+4z=3 z+x-3y=5 2x+y+z=7 2x-z=1
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解方程组x+2y+3z=10,x-y+4z=10,x+3y+2z=2.
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X+y-z=6;x-3y+2z=0;3x+2y-z=4
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x+y+z=4 3x-y-2z=0 x+2y-z=-6