cosx+√3sinx=2(1/2cosx+√3/2sinx)=2(sinπ/6cosx+cosπ/6sinx)=2sin(x+π/6)
为什么cosx+√3sinx=2sin(x+π/6)
0
0
1个回答
-
00
相关问题
-
为什么y=√3cosx+sinx=2sin(x+π/3)00
-
为什么cosx+根号3sinx=2sin(x+3/π)00
-
求解:f(x)=2sinx*(π/2-x)-√3sin(π+x)cosx+sin(π/2+x)cosx00
-
2sin(x-π/4)sin(x+π/4)=(sinx-cosx)(sinx+cosx)=-cos2a00
-
y=√3sinx+cosx怎么到y=2sin(x+π/6)?00
-
为什么根号三倍sinx+cosx=2sin(x+6分之一π)00
-
f(x)=4sin^2[(π+2x)/4].sinx+(cosx+sinx)(cosx-sinx)00
-
已知函数f(x)=2cosx*sin(x+π/3)-√3sin^2x+sinx*cosx00
-
化简:(1)3/2cosx-√3/2sinx(2)√3sinx/2+cosx/2(3)√2/4sin(π/4-x)+√600
-
f(x)=2cos*sin(x+π/3)-^3sin^2x+sinx*cosx00