∫sint*sintdt怎么求? - 知识问答

∫sint*sintdt怎么求?

2个回答

∫ (sin^2 t) dt
= (1/2) ∫ (2sin^2 t) dt
= (1/2) ∫ (2sin^2 t - 1) dt + (1/2) ∫dt
= (-1/2) ∫ (cos(2t)) dt + 1/2 t
= (-1/4) ∫ (cos(2t)) d(2t) + 1/2 t
= (-1/4) sin(2t) + 1/2 t + C
= -1/4 sintcost + 1/2 t + C

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