2x的2次方y-8xy+8y 怎么分解因式?

1个回答

2x的2次方y-8xy+8y
=2y(x^2-4x+4)
=2y(x-2)^2
a^2(x-y)-4b^2(x-y)
=[a^(x-y)+2b^(x-y)][a^(x-y)-2b^(x-y)]