Question

因式分解：(1)4（2p+3q)^2-9(3p-q)^2 (2)(a+b+c)^2-(a-b-c)^2 (^2代表平方）

Answer 1

：(1)4（2p+3q)^2-9(3p-q)^2 ={2（2p+3q)+3(3p-q)}={2（2p+3q)-3(3p-q)}=(13p+3q)(9q-5P)

(2)(a+b+c)^2-(a-b-c)^2 ={)(a+b+c)-(a-b-c)}{)(a+b+c)+(a-b-c)}=4a(b+c)