①连B1D1交A1C1于O1
A1C1⊥B1D1
∵BB1⊥平面A1B1C1
∴BB1⊥A1C1
∵B1D1∩BB1=平面BB1D1D
∴A1C1⊥平面BB1D1D
∵B1O∈平面BB1D1D
∴A1C1⊥B1O
得证
②连DO1
易证B1O∥DO1
∵DO1∈平面DA1C1
∴B1O∥平面DA1C1
①连B1D1交A1C1于O1
A1C1⊥B1D1
∵BB1⊥平面A1B1C1
∴BB1⊥A1C1
∵B1D1∩BB1=平面BB1D1D
∴A1C1⊥平面BB1D1D
∵B1O∈平面BB1D1D
∴A1C1⊥B1O
得证
②连DO1
易证B1O∥DO1
∵DO1∈平面DA1C1
∴B1O∥平面DA1C1