1/2+1/4+1/8+1/16+1/32+1/64+1/128+1/256=?直接写得数.
3个回答
这是个等比数列哦,等比是1/2
由公式的:[a1(1-q的n次幂)]/(1-q) a1 是第一项
所以:【1/2(1-(1/2)的8次方)】/(1-1/2)=255/256
相关问题
1+1?2+2?4+4?8+8?16+16?32+32 64+64 128+128 256+256 512+512 10
1/2+1/4+1/8+1/16+1/32+1/64+1/128+1/256
1/2-1/4-1/8-1/16-1/32-1/64-1/128-1/256
1/2+1/4+1/8+1/16+1/32+1/64+1/128+1/256=?
1/2-1/4-1/8-16/1-32/1-64/1-128/1-256/1
1/2+1/4+1/8+1/16+1/32+1/64+1/128+1/256
1+2\1+4\1+8\1+16\1+32\1+64\1+128\1+256\1
计算:1/2+4/1+8/1+16/1+32/1+64/1+128/1+256/1
1-1/2+1/4-1/8+1/16-1/32+1/64-1/128+1/128+1/256-1/512
1+[1/2]+[1/4]+[1/8]+[1/16]+[1/32]+[1/64]+[1/128]+[1/256]+[1/