（x+y)³+2xy-2x²y-2xy²-1
=(x+y)³-1 -2xy(x+y-1)
=(x+y-1)[(x+y)²+(x+y)+1]-2xy(x+y-1)
=(x+y-1)[(x+y)²+(x+y)+1-2xy]
=(x+y-1)(x²+y²+x+y+1)
因式分解：（x+y)³+2xy-2x²y-2xy²-1
1个回答
相关问题
-
因式分解:(x+y-2xy)(x+y-2)+(xy-1)^2
-
因式分解：（x+y）（x+y+2xy）+（xy+1）（xy-1）=______．
-
因式分解：（x+y）（x+y+2xy）+（xy+1）（xy-1）=______．
-
（xy-1）平方+（x+y-2xy）（x+y-2）因式分解
-
因式分解(x+y)^3+2xy-2x^2y-2xy^2-1
-
暑假作业因式分解(x+y-2xy)(x+y)+(xy-1)2
-
因式分解(x+y)立方+2xy-2x平方y-2xy平方-1
-
(x^3+y^3)^2-4xy[x^4+x^2y^2+y^4-2xy(x^2-xy+y^2)]因式分解
-
x^2+y^2-x-y-xy+1如何因式分解
-
因式分解:12xy^2(y-x)+xy^3(x-y)+4x^2y(x-y)