25a²-100（b+c)²
＝(5a)²-[10(b+c)]²
=[5a+10(b+c)][5a-10(b+c)]
=5(a+2b+2c)×5(a-2b-2c)
=25(a+2b+2c)(a-2b-2c)
25a²-100（b+c)²因式分解（求过程）
25a²-100（b+c)²
＝(5a)²-[10(b+c)]²
=[5a+10(b+c)][5a-10(b+c)]
=5(a+2b+2c)×5(a-2b-2c)
=25(a+2b+2c)(a-2b-2c)