Question

【（-2x^2y^3)^2*x-2x(5xy^2)^3】/（9x^2y^6）

Answer 1

[(-2*x^2*y^3)^2*x-2x*(5xy^2)^3]/(9x^2y^6)

=[(4*x^4*y^6)*x-2x*125x^3y^6]/(9x^2y^6)

=(4*x^5*y^6-250*x^4y^6)/(9x^2y^6)

=(4*x^3-250*x^2)/9

=4/9*x^3-250/9*x^2