Question

一道化学基础题98%的浓硫酸的密度为1.84g/ml,1.弄就算的物质的量浓度为___________.2.若将该浓硫酸

Answer 1

1.1000mL (1L) 98%的浓硫酸:

质量1.84*1000 = 1840 g

H2SO4的质量:1840*98% = 1803 g

H2SO4的物质的量:1803/98 = 18.4 mol

H2SO4的物质的量浓度:18.4/1 = 18.4 mol/L

2.溶液质量:1840*2 = 3680 g

溶液的质量分数:1803/3680 = 49%

3.溶液的质量:1840 + 1000 = 2840 g

溶液的质量分数:1803/2840 = 63.5%

4.1*1 = 18.4V

v = 0.0543 L = 54.3 mL