化简(1 +tan^2M)×cos^2M
4个回答
(1 +tan^2M)×cos^2M
=(1+sin^2m/cos^2m)xcos^2m
=cos^2m+sin^2m
=1
相关问题
化简:sin^2α×tanα+cos^2α×cotα+2sinα×cosα
化简求值:(1)化简:(1+tan2α)cos2α;(2)求值:[3/4]tan2[π/6]-tan[π/4]+cos2
化简(1+tan^2 a) cos^2 a
化简(1+tan^2α)cos^2α
已知cos(2α+β)=3cosβ,化简tanα×tan(α+β)
化简,①(2cos²α-1)/(1-2sin²;) ②(1+tan²α)cos²
化简:[(1/4)×m²-1]²+m²=?
探究规律,解决问题:(1)化简:(m-1)(m+1)=______,(m-1)(m2+m+1)=______.(2)化简
化简:|m|+|m-1|+|m-2|.
tan5°+1/tan5°-2/cos80° 化简求值