Question

xy-2x-2y+8=0的整数解(x≤y)为

Answer 1

xy-2x-2y+8=0;

(x-2)(y-2)+4=0;

(x-2)(y-2)=-4=(-2)x2.

x≤y,则x-2≤y-2,即x-2=-2;y-2=2.

得x=0,y=4.