Question

已知(x05-1)分之(1-3x)=(x+1)分之M+(x-1)分之N,求M、N的值

Answer 1

已知(x²-1)分之(1-3x)=(x+1)分之M+(x-1)分之N,求M、N的值

(x²-1)分之(1-3x)=(x+1)分之M+(x-1)分之N

(1-3x)/(x-1)(x+1)=(mx-m+nx+n)/(x-1)(x+1)

∴1-3x=x(m+n)+(n-m)

m+n=-3

n-m=1

∴m=-2

n=-1