let X be the length of the triangle
3(X+6)+4X=53
3X+18+4X=53
7X =53-18
7X=35
X=5
the length of the shorter wire is
5cm×4=20cm
the length of the loner wire is
(5+6) ×3= 33cm
let X be the length of the triangle
3(X+6)+4X=53
3X+18+4X=53
7X =53-18
7X=35
X=5
the length of the shorter wire is
5cm×4=20cm
the length of the loner wire is
(5+6) ×3= 33cm