Question

求级数s=1/(1+1)+2/(1+2*2)+3/(1+3*3)+……n/(1+n*n)的前250项之和(取2位小数,第

Answer 1

7.求级数s=1/(1+1)+2/(1+2*2)+3/(1+3*3)+-------+n/(1+n*n)+-------的前200项之和（取一位小数,第二位小数四舍五入）

编写程序代码

Private Sub Form_Click()

Dim n As Integer

Dim s As Single

n = 1: s = 0

Do While n