设公差为d
由题意,
S1=a1
S2=2a1+d
S4=4a1+6d
a1*(4a1+6d)=(2a1+d)^2
d^2-2a1*d=0
d(d-2a1)=0
d不等于0
所以d=2a1
(1)
公比q=S2/S1=(2a1+d)/a1=(4a1)/a1=4
(2)
S2=a1+a2=2a1+d=4a1=4
a1=1
d=2a1=2
an=a1+(n-1)d=1+(n-1)*2=2n-1
设公差为d
由题意,
S1=a1
S2=2a1+d
S4=4a1+6d
a1*(4a1+6d)=(2a1+d)^2
d^2-2a1*d=0
d(d-2a1)=0
d不等于0
所以d=2a1
(1)
公比q=S2/S1=(2a1+d)/a1=(4a1)/a1=4
(2)
S2=a1+a2=2a1+d=4a1=4
a1=1
d=2a1=2
an=a1+(n-1)d=1+(n-1)*2=2n-1