Question

问一道数学求周期的题!y=(1-tan3x)/(1+tan3x) 求此函数的周期?

Answer 1

``````````1`-`tan`3x`````````tan`45°-`tan 3x``````````````````

````y=--------------- = -------------------------```````````````

``````````1`+`tan`3x```````1`+`tan`45°×tan 3x````````````

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`````=tan(45°-3x) (差角公式)`````````````````````

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````∴ω`=`3``````````````````````````````````````

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````````````π```π```````````````````````````````

````∴T`=`-`=`-`````````````````````````````````

````````````ω```3```````````````````````````````