1.设AB长度=a
BC=1/3a
CD=1/3*1/3a
DE=1/3*1/3*1/3a
AE=a+1/3a+1/3*1/3a+1/3*1/3*1/3a=80 =>a=54
2.AB=5,AC=7 =>BC=2
BC=2 BD=4BC =>BD=8
BC-AB=AD =>AD=3
=>CD=10
=>DE(CE)=5
DE-AD=AE =>5-3=2
AE=2,CD=10 =>AE=1/5CD
1.设AB长度=a
BC=1/3a
CD=1/3*1/3a
DE=1/3*1/3*1/3a
AE=a+1/3a+1/3*1/3a+1/3*1/3*1/3a=80 =>a=54
2.AB=5,AC=7 =>BC=2
BC=2 BD=4BC =>BD=8
BC-AB=AD =>AD=3
=>CD=10
=>DE(CE)=5
DE-AD=AE =>5-3=2
AE=2,CD=10 =>AE=1/5CD