数学二元一次方程组(请帮忙写出具体步骤)

8个回答

  • (1)a=2b+3 ------>①

    a=3b+20----->②

    把①式代入② 得:2b+3=3b+20 经过变形:b=-17--->③

    把③式代入①式,得:a=-31

    (2) x-y=4 ------>①

    4x+2y=-1----->②

    ①式乘2加上② 式得:6x=7 --->x=7/6-------->③

    ③式代入①得:y=-17/6

    (3) 4(x-y-1)=3(1-y)-2------>①

    x/2+y/3=2----->②

    ①式化简得:4x-y=5----->③

    ②式化简得:3x+2y=12----->④

    ③式乘2加上④得:11x=22----->x=2 把x=2代入③得:y=3

    (4) 2(x-y)/3-x+y/4=-1------>①

    6(x+y)-4(2x-y)=16---->②

    ①式化简得:4x+5y=12----->③

    ②式化简得:5y-x=8----->④

    ③式减去④得:5x=4--->x=4/5 把x=4/5代入③得:y=44/25