已知方程组﹛x+4y-3z=0 4x-5y+2z=0 ,xyz≠0,求﹙3x²+2xy+z²﹚÷﹙x
1个回答
令z=3,代入方程组得到:
①x+4y=9,
②4x-5y=-6,
解得:x=1,y=2,
再代入原式得:
﹙3×1²+2×1×2+3²﹚/﹙1²+2²﹚
=16/5
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