Question

将一块铁块放入盛满酒精的杯中时,有8g溢出 则铁块的体积? 质量?

Answer 1

1.V=m/p=8g/0.8g/cm^3=10cm^3

m=pV=7.9g/cm^3*10cm^3=79g

2.m=pV=0.9*10^3kg/m^3*0.2m^3=0.18kg

V=m/p=180g/1g/cm^3=180cm^3

3.我把156换成了158

V=m/p=158g/7.9g/cm^3=20cm^3

V空=V总-V=30cm^3-20cm^3=10cm^3

m=pV=11.3g/cm^3*10cm^3=113g

m总=m1+m2=113g+158g=271g