x^2-3x+1=0,求1/(x^4+x^2+1)等于多少
3个回答
x^2-3x+1=0
x1=(3+√5)/2,x2=(3-√5)/2
1/(x^4+x^2+1)=1/8x^2=1/(28+12√5)或1/(28-12√5)
相关问题
(2x3X4X5)X(2/1-3/1-4/1+5/1)等于多少?
2(x-2)-3(4x-1)=9(1-x)x=等于多少
1、 X/X^2+X+1=a(a不等于0,1/2) 求 x^2/x^4+x^2+1
求方程组X1-3X2-2X3-X4=1 3X1-8X2-4X3-X4=0 -2X1+X2-4X3+2X4=1 -X1-2
如果 x^2-3x+1=0 ,那么x^2+1/x^2 等于多少?
求线性方程组{X1+X2+2X3-3X4=0; X1+2X2-X3+2X4=0; 2X1+3X2+X3-X4=0}的基础
求线性方程组 x2-x3-x4=0 x1+x2-x3+3x4=1 x1-x2+x3+5x4=-1 x1+2x2-2x3+
求齐次线性方程组(大括号)x1+2X3-x4=0 -x1+x2-3x3+2x4=0 2x1-x2+5x3-3x4=0 求
求齐次线性方程组(大括号)x1+2X3-x4=0 -x1+x2-3x3+2x4=0 2x1-x2+5x3-3x4=0 求
X1×X2是方程X^-3X-2=0的两根 求X^+3X1×X2+2X^等于多少