Question

已知(a-2) 2;+丨b+1丨=0,求(-a-b)的2010次方+2的8次方×(-a分之1)的9次方的值

Answer 1

(a-2) 2;+丨b+1丨=0,

因为(a-2) 2>=0,丨b+1丨>=0,

所以a-2=0,b+1=0

a=2,b=-1

(-a-b)的2010次方+2的8次方×(-a分之1)的9次方

=(-2+1)^2010+2^8*(-1/2)^9

=1+2^8*1/2^9

=1+1/2

3/2