Question

设集合A=[0,1／2],B=[1／2,1],函数f(x)={①x+1／2,x∈A,②2(1-x),x∈B,若x0∈A,

Answer 1

x0∈A 则x0+1/2∈B

f(f(x0))=f(x0+1/2)=2[1-(x0+1/2)]=1-2x0∈A

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