求式子I1/3-1/2I+I1/4-1/3I+I1/5-1/4I+.+I1/10-1/9I=
2个回答
I1/3-1/2I+I1/4-1/3I+I1/5-1/4I+.+I1/10-1/9I
=1/2-1/3+1/3-1/4+1/4-1/5+……+1/9-1/10
=1/2-1/10
=2/5
相关问题
(1)i/1+i(2)2/(1+i)^2(3)(3-i)/(3+4i)(4)(3-4i)(1+2i)/2i
I1/2-1I+I1/3-1/2I+...+I1/9-1/8I+I1/10-1/9I I I是绝对值的符号
复数计算(1)(1+i)^7/1-i +(1-i)^7/1+i -(3-4i)(2+2i)^3/4+3i (2)1/i(
计算:(1)5-(3+2i) (2)(-3-4i)+(2+i)-(1-5i) (3)(2-i)-(2+3i)+4i
(1) (1-i⒌)+(2-i⒎)+(3-i⒐)+(4-i⒒)
1.R1:R2:R3:R4=1:2:3:4 求I1:I2:I3:I4
(3-4i/1+2i)+(2+i^15)-(1+i/1-i)^100=
(1+i)^2(3-4i)/1-i
(1-3i)-(2+5i)+(-4+9i)等于?
请帮忙解一个方程组,急用I1+I2+I3=05I1-10I3=15 求I1、 I2 、 I3的值,-10I2+10I3=